task_id stringlengths 11 13 | prompt stringlengths 115 1.36k | canonical_solution stringlengths 19 865 | entry_point stringlengths 1 30 | test stringlengths 928 502k | question stringlengths 0 1.23k | starter_code stringlengths 10 775 |
|---|---|---|---|---|---|---|
HumanEval/100 |
def make_a_pile(n):
"""
Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each lev... |
ans, num = [], n
for _ in range(n):
ans.append(num)
num += 2
return ans
| make_a_pile | import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtype ... | Given a positive integer n, you have to make a pile of n levels of stones.
The first level has n stones.
The number of stones in the next level is:
- the next odd number if n is odd.
- the next even number if n is even.
Return the number of stones in each level in a list, where element at index
i represents the... | def make_a_pile(n):
|
HumanEval/101 |
def words_string(s):
"""
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
words_string("One, two, three, fo... |
words = (s.replace(",", " ")).split()
return [word for word in words if word != ""]
| words_string |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
words_string("One, two, three, four, five, six") == ["One", "two", "three", "four", "fi... | def words_string(s):
|
HumanEval/102 |
def choose_num(x, y):
"""This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
choose_num(12, 15) = 14
choose_num(13, 12) = -1
"""
|
if x > y: return -1
if x == y: return y if y % 2 == 0 else -1
return y if y % 2 == 0 else y - 1
| choose_num |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | This function takes two positive numbers x and y and returns the
biggest even integer number that is in the range [x, y] inclusive. If
there's no such number, then the function should return -1.
For example:
choose_num(12, 15) = 14
choose_num(13, 12) = -1 | def choose_num(x, y):
|
HumanEval/103 |
def rounded_avg(n, m):
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
rounded_avg(1, 5)... |
if n > m: return -1
avg = round((n + m) / 2)
return bin(avg)
| rounded_avg |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
rounded_avg(1, 5) => "0b11"
rounded_avg(7, 5) => -1
rounded_avg(10, ... | def rounded_avg(n, m):
|
HumanEval/104 |
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10... |
def judge(x):
for ch in str(x):
if int(ch) % 2 == 0:
return False
return True
return sorted(list(filter(judge, x)))
| unique_digits |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.
Note: Returned list should be sorted in increasing order.
For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[] | def unique_digits(x):
|
HumanEval/105 |
def by_length(arr):
"""
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
arr = [2, 1, ... |
def to_word(x: int) -> str:
if x == 1:
return "One"
elif x == 2:
return "Two"
elif x == 3:
return "Three"
elif x == 4:
return "Four"
elif x == 5:
return "Five"
elif x == 6:
return "Six"
elif x == 7:
return "Seven"
... | by_length |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
arr = [2, 1, 1, 4, 5, 8, 2, 3]
-> sort arr -> [1, 1... | def by_length(arr):
|
HumanEval/106 |
def f(n):
""" Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers fr... |
if n == 0: return []
if n == 1: return [1]
if n == 2: return [1, 2]
ans = [1, 2]
for i in range(3, n + 1):
if i % 2 == 1:
ans.append(ans[-2] + (i - 1) + i)
else:
ans.append(ans[-2] * (i - 1) * i)
return ans
| f |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Implement the function f that takes n as a parameter,
and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even
or the sum of numbers from 1 to i otherwise.
i starts from 1.
the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).
Exampl... | def f(n):
|
HumanEval/107 |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them i... |
odd_cnt, even_cnt = 0, 0
for i in range(1, n + 1):
if str(i) == str(i)[::-1]:
if i % 2 == 1:
odd_cnt += 1
else:
even_cnt += 1
return even_cnt, odd_cnt
| even_odd_palindrome |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.
Example 2:
Input: 12
O... | def even_odd_palindrome(n):
|
HumanEval/108 |
def count_nums(arr):
"""
Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
>>> count_nums([]) == 0
>>... |
def judge(x: int) -> int:
l = list(str(x))
if l[0] == "-":
l = l[1:]
l = list(map(int, l))
l[0] = -l[0]
else:
l = list(map(int, l))
return 1 if sum(l) > 0 else 0
return sum(map(judge, arr))
| count_nums |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Write a function count_nums which takes an array of integers and returns
the number of elements which has a sum of digits > 0.
If a number is negative, then its first signed digit will be negative:
e.g. -123 has signed digits -1, 2, and 3.
>>> count_nums([]) == 0
>>> count_nums([-1, 11, -11]) == 1
>>> count_nums([1, 1,... | def count_nums(arr):
|
HumanEval/109 |
def move_one_ball(arr):
"""We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
Yo... |
sorted_arr = sorted(arr)
if arr == sorted_arr: return True
for i in range(1, len(arr)):
if arr[i:] + arr[:i] == sorted_arr:
return True
return False
| move_one_ball |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The
numbers in the array will be randomly ordered. Your task is to determine if
it is possible to get an array sorted in non-decreasing order by performing
the following operation on the given array:
You are allowed to perform right shift operation a... | def move_one_ball(arr):
|
HumanEval/110 |
def exchange(lst1, lst2):
"""In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1... |
cnt_odd = len(list(filter(lambda x: x % 2 == 1, lst1)))
cnt_even = len(list(filter(lambda x: x % 2 == 0, lst2)))
return "YES" if cnt_odd <= cnt_even else "NO"
| exchange |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | In this problem, you will implement a function that takes two lists of numbers,
and determines whether it is possible to perform an exchange of elements
between them to make lst1 a list of only even numbers.
There is no limit on the number of exchanged elements between lst1 and lst2.
If it is possible to exchange eleme... | def exchange(lst1, lst2):
|
HumanEval/111 |
def histogram(test):
"""Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram('a b c') == {'a': 1, '... |
if test == "": return {}
count, ans = dict(), dict()
for word in test.split(" "):
if word != "":
if word not in count: count[word] = 0
count[word] += 1
mx = max(list(count.values()))
for ch, c in count.items():
if c == mx:
ans[ch] = c
ret... | histogram |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a string representing a space separated lowercase letters, return a dictionary
of the letter with the most repetition and containing the corresponding count.
If several letters have the same occurrence, return all of them.
Example:
histogram('a b c') == {'a': 1, 'b': 1, 'c': 1}
histogram('a b b a') == {'a': 2, '... | def histogram(test):
|
HumanEval/112 |
def reverse_delete(s,c):
"""Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple contai... |
ss = "".join(filter(lambda ch: ch not in c, s))
return ss, ss == ss[::-1]
| reverse_delete |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Task
We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c
then check if the result string is palindrome.
A string is called palindrome if it reads the same backward as forward.
You should return a tuple containing the result string and True/False for the che... | def reverse_delete(s,c):
|
HumanEval/113 |
def odd_count(lst):
"""Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
... |
ans, template = [], "the number of odd elements in the string i of the input."
for s in lst:
odd_cnt = len(list(filter(lambda ch: int(ch) % 2 == 1, s)))
ans.append(template.replace("i", str(odd_cnt)))
return ans
| odd_count |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a list of strings, where each string consists of only digits, return a list.
Each element i of the output should be "the number of odd elements in the
string i of the input." where all the i's should be replaced by the number
of odd digits in the i'th string of the input.
>>> odd_count(['1234567'])
["the number ... | def odd_count(lst):
|
HumanEval/114 |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
minSubArraySum([-1, -2, -3]) == -6
"""
|
if all(x >= 0 for x in nums): return min(nums)
s, ans = 0, 0
for x in nums:
s += x
ans = min(ans, s)
if s >= 0: s = 0
return ans
| minSubArraySum |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
minSubArraySum([-1, -2, -3]) == -6 | def minSubArraySum(nums):
|
HumanEval/115 | import math
def max_fill(grid, capacity):
"""
You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.... |
ans = 0
for l in grid:
ans += math.ceil(sum(l) / capacity)
return ans
| max_fill |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given a rectangular grid of wells. Each row represents a single well,
and each 1 in a row represents a single unit of water.
Each well has a corresponding bucket that can be used to extract water from it,
and all buckets have the same capacity.
Your task is to use the buckets to empty the wells.
Output the num... | import math
def max_fill(grid, capacity):
|
HumanEval/116 |
def sort_array(arr):
"""
In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
>>> sort_array([1, 5, 2, 3, 4]) ==... |
from functools import cmp_to_key
def cmp(x: int, y: int) -> int:
x1 = len(list(filter(lambda ch: ch == "1", bin(x))))
y1 = len(list(filter(lambda ch: ch == "1", bin(y))))
if x1 != y1: return x1 - y1
return x - y
return sorted(arr, key=cmp_to_key(cmp))
| sort_array |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | In this Kata, you have to sort an array of non-negative integers according to
number of ones in their binary representation in ascending order.
For similar number of ones, sort based on decimal value.
It must be implemented like this:
>>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5]
>>> sort_array([-2, -3, -4, -5, -... | def sort_array(arr):
|
HumanEval/117 |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an e... |
ans = []
for word in s.split(" "):
if word != "":
c_cnt = len(list(filter(lambda ch: ch not in "aeiouAEIOU", word)))
if c_cnt == n: ans.append(word)
return ans
| select_words |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an empty list.
Note: you may assume the input st... | def select_words(s, n):
|
HumanEval/118 |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condit... |
def is_vowel(ch: str) -> bool:
return ch in "aeiouAEIOU"
for i in range(len(word) - 2, 0, -1):
if is_vowel(word[i]) and not is_vowel(word[i-1]) and not is_vowel(word[i+1]):
return word[i]
return ""
| get_closest_vowel |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains ... | def get_closest_vowel(word):
|
HumanEval/119 |
def match_parens(lst):
'''
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be... |
def valid_parens(s: str) -> bool:
cnt = 0
for ch in s:
cnt = cnt + 1 if ch == "(" else cnt - 1
if cnt < 0: return False
return cnt == 0
return "Yes" if valid_parens(lst[0] + lst[1]) or valid_parens(lst[1] + lst[0]) else "No"
| match_parens |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def match_parens(lst):
'''
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be... | |
HumanEval/120 |
def maximum(arr, k):
"""
Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
Input: arr = [-3, -4, 5], k = 3
Output: [-4, -3, 5]
Example 2:
Input: arr = [4, -4, 4], k = 2
Output:... |
return sorted(sorted(arr)[::-1][:k])
| maximum |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given an array arr of integers and a positive integer k, return a sorted list
of length k with the maximum k numbers in arr.
Example 1:
Input: arr = [-3, -4, 5], k = 3
Output: [-4, -3, 5]
Example 2:
Input: arr = [4, -4, 4], k = 2
Output: [4, 4]
Example 3:
Input: arr = [-3, 2, 1, 2, -1, -2, 1]... | def maximum(arr, k):
|
HumanEval/121 |
def solution(lst):
"""Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution([5, 8, 7, 1]) ==> 12
solution([3, 3, 3, 3, 3]) ==> 9
solution([30, 13, 24, 321]) ==>0
"""
|
return sum(lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 == 1)
| solution |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.
Examples
solution([5, 8, 7, 1]) ==> 12
solution([3, 3, 3, 3, 3]) ==> 9
solution([30, 13, 24, 321]) ==>0 | def solution(lst):
|
HumanEval/122 |
def add_elements(arr, k):
"""
Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
Output: 24 # sum of 21 + 3
Constraints:
... |
def digits(x: int) -> int:
s = str(x)
return len(s) - 1 if s[0] == "-" else len(s)
return sum(filter(lambda x: digits(x) <= 2, arr[:k]))
| add_elements |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a non-empty array of integers arr and an integer k, return
the sum of the elements with at most two digits from the first k elements of arr.
Example:
Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4
Output: 24 # sum of 21 + 3
Constraints:
1. 1 <= len(arr) <= 100
2. 1 <= k <= len(arr) | def add_elements(arr, k):
|
HumanEval/123 |
def get_odd_collatz(n):
"""
Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
prev... |
ans, x = [], n
while x != 1:
if x % 2 == 1: ans.append(x)
x = x // 2 if x % 2 == 0 else x * 3 + 1
ans.append(1)
return sorted(ans)
| get_odd_collatz |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.
The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined
as follows: start with any positive integer n. Then each term is obtained from the
previous term as follows: if the previous term is eve... | def get_odd_collatz(n):
|
HumanEval/124 |
def valid_date(date):
"""You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31... |
days = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
if len(date) != 10: return False
if date[2] != "-" or date[5] != "-": return False
m, d, y = date[:2], date[3:5], date[6:]
if not m.isdigit() or not d.isdigit() or not y.isdigit(): return False
m, d = int(m), int(d)
if not 1 <= m <= 12... | valid_date |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You have to write a function which validates a given date string and
returns True if the date is valid otherwise False.
The date is valid if all of the following rules are satisfied:
1. The date string is not empty.
2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the numb... | def valid_date(date):
|
HumanEval/125 |
def split_words(txt):
'''
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('... |
whitespace = tuple(' \n\r\t')
if any([x in txt for x in whitespace]): return txt.split()
if "," in txt: return txt.split(",")
cnt = 0
for ch in txt:
if ch.islower() and (ord(ch) - ord("a")) % 2 == 1: cnt += 1
return cnt
| split_words |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def split_words(txt):
'''
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('... | |
HumanEval/126 |
def is_sorted(lst):
'''
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
Examples
is_sorted([5]) ➞ True
is_sorted([1, 2, 3, 4, 5]) ➞ True
... |
count = dict()
for x in lst:
if x not in count: count[x] = 0
count[x] += 1
if count[x] > 2: return False
return lst == sorted(lst)
| is_sorted |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def is_sorted(lst):
'''
Given a list of numbers, return whether or not they are sorted
in ascending order. If list has more than 1 duplicate of the same
number, return False. Assume no negative numbers and only integers.
Examples
is_sorted([5]) ➞ True
is_sorted([1, 2, 3, 4, 5]) ➞ True
... | |
HumanEval/127 |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is ass... |
def is_prime(a):
return not (a < 2 or any(a % x == 0 for x in range(2, int(a ** 0.5) + 1)))
if interval1[0] > interval2[0]: interval1, interval2 = interval2, interval1
l, r = interval2[0], min(interval1[1], interval2[1])
return "YES" if is_prime(r - l) else "NO"
| intersection |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is assumed that its start is less or equal its end.
Your task is to de... | def intersection(interval1, interval2):
|
HumanEval/128 |
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
Example:
>>> prod_signs([1, 2, 2, -4]) == -9
... |
if arr == []: return None
if 0 in arr: return 0
s, sgn = 0, 1
for x in arr:
s += abs(x)
sgn *= (x // abs(x))
return s * sgn
| prod_signs |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
Example:
>>> prod_signs([1, 2, 2, -4]) == -9
>>> prod_signs([0, 1]) == 0
>>> prod_signs([]) == None | def prod_signs(arr):
|
HumanEval/129 |
def minPath(grid, k):
"""
Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You... |
N = len(grid)
x, y = 0, 0
for i in range(N):
for j in range(N):
if grid[i][j] == 1:
x, y = i, j
mn = N * N
if x > 0: mn = min(mn, grid[x - 1][y])
if x < N - 1: mn = min(mn, grid[x + 1][y])
if y > 0: mn = min(mn, grid[x][y - 1])
if y < N - 1: mn = min... | minPath |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a grid with N rows and N columns (N >= 2) and a positive integer k,
each cell of the grid contains a value. Every integer in the range [1, N * N]
inclusive appears exactly once on the cells of the grid.
You have to find the minimum path of length k in the grid. You can start
from any cell, and in each step you ... | def minPath(grid, k):
|
HumanEval/130 |
def tri(n):
"""Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + ... |
if n == 0: return [1]
if n == 1: return [1, 3]
ans = [1, 3]
for i in range(2, n + 1):
if i % 2 == 0:
ans.append(1 + i / 2)
else:
ans.append(ans[-1] + ans[-2] + 1 + (i + 1) / 2)
return ans
| tri | import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtype ... | Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in
the last couple centuries. However, what people don't know is Tribonacci sequence.
Tribonacci sequence is defined by the recurrence:
tri(1) = 3
tri(n) = 1 + n / 2, if n is even.
tri(n) = tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.
Fo... | def tri(n):
|
HumanEval/131 |
def digits(n):
"""Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(1) == 1
digits(4) == 0
digits(235) == 15
"""
|
has_odd, prod = False, 1
for ch in str(n):
if int(ch) % 2 == 1:
has_odd = True
prod *= int(ch)
return 0 if not has_odd else prod
| digits |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a positive integer n, return the product of the odd digits.
Return 0 if all digits are even.
For example:
digits(1) == 1
digits(4) == 0
digits(235) == 15 | def digits(n):
|
HumanEval/132 |
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[... |
for i in range(len(string)):
if string[i] == "]": continue
cnt, max_nest = 0, 0
for j in range(i, len(string)):
if string[j] == "[":
cnt += 1
else:
cnt -= 1
max_nest = max(max_nest, cnt)
if cnt == 0:
... | is_nested |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def is_nested(string):
'''
Create a function that takes a string as input which contains only square brackets.
The function should return True if and only if there is a valid subsequence of brackets
where at least one bracket in the subsequence is nested.
is_nested('[[]]') ➞ True
is_nested('[... | |
HumanEval/133 |
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst =... |
import math
return sum(map(lambda x: math.ceil(x) ** 2, lst))
| sum_squares |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst = [1,3,5,7] the output should be 84
For lst = [1.4,4.2,0... | def sum_squares(lst):
|
HumanEval/134 |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... |
if len(txt) == 0: return False
if len(txt) == 1: return txt.isalpha()
return txt[-1].isalpha() and txt[-2] == " "
| check_if_last_char_is_a_letter |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... | |
HumanEval/135 |
def can_arrange(arr):
"""Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) =... |
for i in range(len(arr) - 1, 0, -1):
if not (arr[i] >= arr[i - 1]):
return i
return -1
| can_arrange |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Create a function which returns the largest index of an element which
is not greater than or equal to the element immediately preceding it. If
no such element exists then return -1. The given array will not contain
duplicate values.
Examples:
can_arrange([1,2,4,3,5]) = 3
can_arrange([1,2,3]) = -1 | def can_arrange(arr):
|
HumanEval/136 |
def largest_smallest_integers(lst):
'''
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no negative or positive integers, return them as None.
Examples:
largest_smallest_intege... |
neg = list(filter(lambda x: x < 0, lst))
pos = list(filter(lambda x: x > 0, lst))
return None if neg == [] else max(neg), None if pos == [] else min(pos)
| largest_smallest_integers |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def largest_smallest_integers(lst):
'''
Create a function that returns a tuple (a, b), where 'a' is
the largest of negative integers, and 'b' is the smallest
of positive integers in a list.
If there is no negative or positive integers, return them as None.
Examples:
largest_smallest_intege... | |
HumanEval/137 |
def compare_one(a, b):
"""
Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
... |
num_a = float(str(a).replace(",", "."))
num_b = float(str(b).replace(",", "."))
if num_a == num_b:
return None
return a if num_a > num_b else b
| compare_one |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Create a function that takes integers, floats, or strings representing
real numbers, and returns the larger variable in its given variable type.
Return None if the values are equal.
Note: If a real number is represented as a string, the floating point might be . or ,
compare_one(1, 2.5) ➞ 2.5
compare_one(1, "2,3") ➞ "... | def compare_one(a, b):
|
HumanEval/138 |
def is_equal_to_sum_even(n):
"""Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
is_equal_to_sum_even(4) == False
is_equal_to_sum_even(6) == False
is_equal_to_sum_even(8) == True
"""
|
return n >= 8 and n % 2 == 0
| is_equal_to_sum_even |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
is_equal_to_sum_even(4) == False
is_equal_to_sum_even(6) == False
is_equal_to_sum_even(8) == True | def is_equal_to_sum_even(n):
|
HumanEval/139 |
def special_factorial(n):
"""The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this integer.
... |
fac, ans = 1, 1
for i in range(2, n + 1):
fac *= i
ans *= fac
return ans
| special_factorial | import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtype ... | The Brazilian factorial is defined as:
brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!
where n > 0
For example:
>>> special_factorial(4)
288
The function will receive an integer as input and should return the special
factorial of this integer. | def special_factorial(n):
|
HumanEval/140 |
def fix_spaces(text):
"""
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2")... |
ans = text
for i in range(len(text), 2, -1):
ans = ans.replace(" " * i, "-")
return ans.replace(" ", "_")
| fix_spaces |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2") == "_Example_2"
fix_spaces(" Example 3") == "_Example-3" | def fix_spaces(text):
|
HumanEval/141 |
def file_name_check(file_name):
"""Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be mo... |
if len(list(filter(lambda ch: ch.isdigit(), file_name))) > 3:
return "No"
f_list = file_name.split(".")
if len(f_list) != 2: return "No"
if len(f_list[0]) == 0: return "No"
if not f_list[0][0].isalpha(): return "No"
if f_list[1] not in ["txt", "exe", "dll"]: return "No"
return "Yes"... | file_name_check |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Create a function which takes a string representing a file's name, and returns
'Yes' if the the file's name is valid, and returns 'No' otherwise.
A file's name is considered to be valid if and only if all the following conditions
are met:
- There should not be more than three digits ('0'-'9') in the file's name.
- The... | def file_name_check(file_name):
|
HumanEval/142 |
def sum_squares(lst):
""""
This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the e... |
ans = 0
for i, num in enumerate(lst):
if i % 3 == 0:
ans += num ** 2
elif i % 4 == 0:
ans += num ** 3
else:
ans += num
return ans
| sum_squares |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a
multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not
change the entries in the list whose indexes are not a mul... | def sum_squares(lst):
|
HumanEval/143 |
def words_in_sentence(sentence):
"""
You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new stri... |
def is_prime(a):
return not (a < 2 or any(a % x == 0 for x in range(2, int(a ** 0.5) + 1)))
return " ".join(list(filter(lambda word: is_prime(len(word)), sentence.split(" "))))
| words_in_sentence |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given a string representing a sentence,
the sentence contains some words separated by a space,
and you have to return a string that contains the words from the original sentence,
whose lengths are prime numbers,
the order of the words in the new string should be the same as the original one.
Example 1:
Inp... | def words_in_sentence(sentence):
|
HumanEval/144 |
def simplify(x, n):
"""Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where ... |
x1, x2 = map(int, x.split("/"))
n1, n2 = map(int, n.split("/"))
return (x1 * n1) % (x2 * n2) == 0
| simplify |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Your task is to implement a function that will simplify the expression
x * n. The function returns True if x * n evaluates to a whole number and False
otherwise. Both x and n, are string representation of a fraction, and have the following format,
<numerator>/<denominator> where both numerator and denominator are posit... | def simplify(x, n):
|
HumanEval/145 |
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_poi... |
def weight(x):
x_list = list(str(x))
if x_list[0] == "-":
x_list = x_list[1:]
x_list = list(map(int, x_list))
x_list[0] = -x_list[0]
else:
x_list = list(map(int, x_list))
return sum(x_list)
return sorted(nums, key=weight)
| order_by_points |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_points([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
>>> orde... | def order_by_points(nums):
|
HumanEval/146 |
def specialFilter(nums):
"""Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter(... |
ans, odd = 0, ["1", "3", "5", "7", "9"]
for num in nums:
if num > 10 and str(num)[0] in odd and str(num)[-1] in odd:
ans += 1
return ans
| specialFilter |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Write a function that takes an array of numbers as input and returns
the number of elements in the array that are greater than 10 and both
first and last digits of a number are odd (1, 3, 5, 7, 9).
For example:
specialFilter([15, -73, 14, -15]) => 1
specialFilter([33, -2, -3, 45, 21, 109]) => 2 | def specialFilter(nums):
|
HumanEval/147 |
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
... |
if n <= 2: return False
one_cnt = 1 + (n - 2) // 3 * 2 + (n - 2) % 3
zero_cnt = n - one_cnt
return one_cnt * (one_cnt - 1) * (one_cnt - 2) // 6 + zero_cnt * (zero_cnt - 1) * (zero_cnt - 2) // 6
| get_max_triples |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
Example :
Input: n = 5
Output: 1
Explan... | def get_max_triples(n):
|
HumanEval/148 |
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a ... |
planets = ["Mercury", "Venus", "Earth", "Mars", "Jupiter", "Saturn", "Uranus", "Neptune"]
if planet1 not in planets or planet2 not in planets: return tuple()
i1, i2 = planets.index(planet1), planets.index(planet2)
if i1 > i2: i1, i2 = i2, i1
return tuple(planets[i1 + 1 : i2])
| bf |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def bf(planet1, planet2):
'''
There are eight planets in our solar system: the closerst to the Sun
is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn,
Uranus, Neptune.
Write a function that takes two planet names as strings planet1 and planet2.
The function should return a ... | |
HumanEval/149 |
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
T... |
from functools import cmp_to_key
def cmp(s: str, t: str):
if len(s) != len(t):
return len(s) - len(t)
return -1 if s < t else 1
return sorted(list(filter(lambda s: len(s) % 2 == 0, lst)), key=cmp_to_key(cmp))
| sorted_list_sum |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of ... | def sorted_list_sum(lst):
|
HumanEval/150 |
def x_or_y(n, x, y):
"""A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
for x_or_y(7, 34, 12) == 34
for x_or_y(15, 8, 5) == 5
"""
|
def is_prime(a):
return not (a < 2 or any(a % x == 0 for x in range(2, int(a ** 0.5) + 1)))
return x if is_prime(n) else y
| x_or_y |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | A simple program which should return the value of x if n is
a prime number and should return the value of y otherwise.
Examples:
for x_or_y(7, 34, 12) == 34
for x_or_y(15, 8, 5) == 5 | def x_or_y(n, x, y):
|
HumanEval/151 |
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_dif... |
ans = 0
for num in lst:
if num % 2 == 1 and num > 0 and "." not in str(num):
ans += num ** 2
return ans
| double_the_difference |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_dif... | |
HumanEval/152 |
def compare(game,guess):
"""I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number... |
return [abs(game[i] - guess[i]) for i in range(len(game))]
| compare |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | I think we all remember that feeling when the result of some long-awaited
event is finally known. The feelings and thoughts you have at that moment are
definitely worth noting down and comparing.
Your task is to determine if a person correctly guessed the results of a number of matches.
You are given two arrays of scor... | def compare(game,guess):
|
HumanEval/153 |
def Strongest_Extension(class_name, extensions):
"""You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extens... |
def strength(s: str) -> int:
CAP, SM = 0, 0
for ch in s:
if ch.isupper(): CAP += 1
if ch.islower(): SM += 1
return CAP - SM
max_strength = max(map(strength, extensions))
for e in extensions:
if strength(e) == max_strength:
return class_na... | Strongest_Extension |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You will be given the name of a class (a string) and a list of extensions.
The extensions are to be used to load additional classes to the class. The
strength of the extension is as follows: Let CAP be the number of the uppercase
letters in the extension's name, and let SM be the number of lowercase letters
in the ext... | def Strongest_Extension(class_name, extensions):
|
HumanEval/154 |
def cycpattern_check(a , b):
"""You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("ab... |
if a == b:
return True
if b == "":
return True
for i in range(0, len(b)):
if b[i:] + b[:i] in a:
return True
return False
| cycpattern_check |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word
cycpattern_check("abcd","abd") => False
cycpattern_check("hello","ell") => True
cycpattern_check("whassup","psus") => False
cycpattern_check("abab","baa") => True
cycpattern_check("efef","eeff") =>... | def cycpattern_check(a , b):
|
HumanEval/155 |
def even_odd_count(num):
"""Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2)
"""
|
even, odd = 0, 0
for ch in str(num):
if ch in "02468": even += 1
if ch in "13579": odd += 1
return even, odd
| even_odd_count |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given an integer. return a tuple that has the number of even and odd digits respectively.
Example:
even_odd_count(-12) ==> (1, 1)
even_odd_count(123) ==> (1, 2) | def even_odd_count(num):
|
HumanEval/156 |
def int_to_mini_roman(number):
"""
Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxx... |
m = ["", "m"]
c = ["", "c", "cc", "ccc", "cd", "d", "dc", "dcc", "dccc", "cm"]
x = ["", "x", "xx", "xxx", "xl", "l", "lx", "lxx", "lxxx", "xc"]
i = ["", "i", "ii", "iii", "iv", "v", "vi", "vii", "viii", "ix"]
thousands = m[number // 1000]
hundreds = c[(number % 1000) // 100]
tens = x[(numb... | int_to_mini_roman |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a positive integer, obtain its roman numeral equivalent as a string,
and return it in lowercase.
Restrictions: 1 <= num <= 1000
Examples:
>>> int_to_mini_roman(19) == 'xix'
>>> int_to_mini_roman(152) == 'clii'
>>> int_to_mini_roman(426) == 'cdxxvi' | def int_to_mini_roman(number):
|
HumanEval/157 |
def right_angle_triangle(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return True if the three
sides form a right-angled triangle, False otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
right_angle_triangle(3, 4,... |
return a ** 2 + b ** 2 == c ** 2 or a ** 2 + c ** 2 == b ** 2 or b ** 2 + c ** 2 == a ** 2
| right_angle_triangle |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... |
def right_angle_triangle(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return True if the three
sides form a right-angled triangle, False otherwise.
A right-angled triangle is a triangle in which one angle is right angle or
90 degree.
Example:
right_angle_triangle(3, 4,... | |
HumanEval/158 |
def find_max(words):
"""Write a function that accepts a list of strings.
The list contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
find_max(["... |
mx_ch_cnt, ans = 0, ""
for word in words:
ch_cnt = len(set(word))
if ch_cnt > mx_ch_cnt or (ch_cnt == mx_ch_cnt and word < ans):
mx_ch_cnt, ans = ch_cnt, word
return ans
| find_max |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Write a function that accepts a list of strings.
The list contains different words. Return the word with maximum number
of unique characters. If multiple strings have maximum number of unique
characters, return the one which comes first in lexicographical order.
find_max(["name", "of", "string"]) == "string"
find_max(... | def find_max(words):
|
HumanEval/159 |
def eat(number, need, remaining):
"""
You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the... |
if need <= remaining:
return [number + need, remaining - need]
else:
return [number + remaining, 0]
| eat |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You're a hungry rabbit, and you already have eaten a certain number of carrots,
but now you need to eat more carrots to complete the day's meals.
you should return an array of [ total number of eaten carrots after your meals,
the number of carrots left after your meals ]
if there are not... | def eat(number, need, remaining):
|
HumanEval/160 |
def do_algebra(operator, operand):
"""
Given two lists operator, and operand. The first list has basic algebra operations, and
the second list is a list of integers. Use the two given lists to build the algebric
expression and return the evaluation of this expression.
The basic algebra operation... |
exp = ""
for i in range(len(operator)):
exp += str(operand[i]) + operator[i]
exp += str(operand[-1])
return eval(exp)
| do_algebra |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given two lists operator, and operand. The first list has basic algebra operations, and
the second list is a list of integers. Use the two given lists to build the algebric
expression and return the evaluation of this expression.
The basic algebra operations:
Addition ( + )
Subtraction ( - )
Multiplication ( * )
... | def do_algebra(operator, operand):
|
HumanEval/161 |
def solve(s):
"""You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("... |
ans, has_letter = "", False
for ch in s:
if ch.isalpha():
has_letter = True
ans += ch.swapcase()
else:
ans += ch
return ans if has_letter else s[::-1]
| solve |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | You are given a string s.
if s[i] is a letter, reverse its case from lower to upper or vise versa,
otherwise keep it as it is.
If the string contains no letters, reverse the string.
The function should return the resulted string.
Examples
solve("1234") = "4321"
solve("ab") = "AB"
solve("#a@C") = "#A@c" | def solve(s):
|
HumanEval/162 |
def string_to_md5(text):
"""
Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62'
"""
|
if text == "": return None
import hashlib
m = hashlib.md5()
m.update(text.encode("utf-8"))
return m.hexdigest()
| string_to_md5 |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given a string 'text', return its md5 hash equivalent string.
If 'text' is an empty string, return None.
>>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62' | def string_to_md5(text):
|
HumanEval/163 |
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
|
if a > b: a, b = b, a
return [i for i in range(a, min(b + 1, 10)) if i % 2 == 0]
| generate_integers |
import numpy as np
def is_floats(x) -> bool:
# check if it is float; List[float]; Tuple[float]
if isinstance(x, float):
return True
if isinstance(x, (list, tuple)):
return all(isinstance(i, float) for i in x)
if isinstance(x, np.ndarray):
return x.dtype == np.float64 or x.dtyp... | Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => [] | def generate_integers(a, b):
|
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