Datasets:

---

FFHow

/

OlympiadBench

like 0

Error code:   DatasetGenerationError
Exception:    ArrowInvalid
Message:      Failed to parse string: 'Global Positioning System (GPS) is a navigation technology which uses signal from satellites to determine the position of an object (for example an airplane). However, due to the satellites high speed movement in orbit, there should be a special relativistic correction, and due to their high altitude, there should be a general relativistic correction. Both corrections seem to be small but are very important for precise measurement of position. We will explore both corrections in this problem.

First we will investigate the special relativistic effect on an accelerated particle. We consider two types of frame, the first one is the rest frame (called $S$ or Earth's frame), where the particle is at rest initially. The other is the proper frame (called $S^{\prime}$ ), a frame that instantaneously moves together with the accelerated particle. Note that this is not an accelerated frame, it is a constant velocity frame that at a particular moment has the same velocity with the accelerated particle. At that short moment, the time rate experienced by the particle is the same as the proper frame's time rate. Of course this proper frame is only good for an infinitesimally short time, and then we need to define a new proper frame afterward. At the beginning we synchronize the particle's clock with the clock in the rest frame by setting them to zero, $t=\tau=0$ ( $t$ is the time in the rest frame, and $\tau$ is the time shown by particle's clock).

By applying equivalence principle, we can obtain general relativistic effects from special relavistic results which does not involve complicated metric tensor calculations. By combining the special and general relativistic effects, we can calculate the corrections needed for a GPS (global positioning system) satellite to provide accurate positioning.

Some mathematics formulas that might be useful

- $\sinh x=\frac{e^{x}-e^{-x}}{2}$
- $\cosh x=\frac{e^{x}+e^{-x}}{2}$
- $\tanh x=\frac{\sinh x}{\cosh x}$
- $1+\sinh ^{2} x=\cosh ^{2} x$
- $\sinh (x-y)=\sinh x \cosh y-\cosh x \sinh y$



- $\int \frac{d x}{\left(1-x^{2}\right)^{\frac{3}{2}}}=\frac{x}{\sqrt{1-x^{2}}}+C$
- $\int \frac{d x}{1-x^{2}}=\ln \sqrt{\frac{1+x}{1-x}}+C$


Part A. Single Accelerated Particle 

Consider a particle with a rest mass $m$ under a constant and uniform force field $F$ (defined in the rest frame) pointing in the positive $x$ direction. Initially $(t=\tau=0)$ the particle is at rest at the origin $(x=0)$.
Context question:
1.  When the velocity of the particle is $v$, calculate the acceleration of the particle, $a$ (with respect to the rest frame).
Context answer:
\boxed{$a=\frac{F}{\gamma^{3} m}$}


Context question:
2.  Calculate the velocity of the particle $\beta(t)=\frac{v(t)}{c}$ at time $t$ (in rest frame), in terms of $F, m, t$ and $c$.
Context answer:
\boxed{$\beta=\frac{\frac{F t}{m c}}{\sqrt{1+\left(\frac{F t}{m c}\right)^{2}}}$}


Context question:
3.  Calculate the position of the particle $x(t)$ at time $t$, in term of $F, m, t$ and $c$.
Context answer:
\boxed{$x=\frac{m c^{2}}{F}\left(\sqrt{1+\left(\frac{F t}{m c}\right)^{2}}-1\right)$}


Context question:
4.  Show that the proper acceleration of the particle, $a^{\prime} \equiv g=F / m$, is a constant. The proper acceleration is the acceleration of the particle measured in the instantaneous proper frame.
Context answer:
\boxed{证明题}


Context question:
5.  Calculate the velocity of the particle $\beta(\tau)$, when the time as experienced by the particle is $\tau$. Express the answer in $g, \tau$, and $c$.
Context answer:
\boxed{$\beta=\tanh \frac{g \tau}{c}$}


Context question:
6. ( $\mathbf{0 . 4} \mathbf{~ p t s )}$ Also calculate the time $t$ in the rest frame in terms of $g, \tau$, and $c$.
Context answer:
\boxed{$t=\frac{c}{g} \sinh \frac{g \tau}{c}$}


Extra Supplementary Reading Materials:

Part B. Flight Time 

The first part has not taken into account the flight time of the information to arrive to the observer. This part is the only part in the whole problem where the flight time is considered. The particle moves as in part A.
Context question:
1.  At a certain moment, the time experienced by the particle is $\tau$. What reading $t_{0}$ on a stationary clock located at $x=0$ will be observed by the particle? After a long period of time, does the observed reading $t_{0}$ approach a certain value? If so, what is the value?
Context answer:
\boxed{证明题}


Context question:
2.  Now consider the opposite point of view. If an observer at the initial point $(x=0)$ is observing the particle's clock when the observer's time is $t$, what is the reading of the particle's clock $\tau_{0}$ ? After a long period of time, will this reading approach a certain value? If so, what is the value?
Context answer:
\boxed{证明题}


Extra Supplementary Reading Materials:

Part C. Minkowski Diagram

In many occasion, it is very useful to illustrate relativistic events using a diagram, called as Minkowski Diagram. To make the diagram, we just need to use Lorentz transformation between the rest frame $S$ and the moving frame $S^{\prime}$ that move with velocity $v=\beta c$ with respect to the rest frame.

$$
\begin{aligned}
& x=\gamma\left(x^{\prime}+\beta c t^{\prime}\right), \\
& c t=\gamma\left(c t^{\prime}+\beta x^{\prime}\right), \\
& x^{\prime}=\gamma(x-\beta c t), \\
& c t^{\prime}=\gamma(c t-\beta x) . \\
& \gamma=\frac{1}{\sqrt{1-\frac{v^{2}}{c^{2}}}}
\end{aligned}
$$

<image_1>

Let's choose $x$ and $c t$ as the orthogonal axes. A point $\left(x^{\prime}, c t^{\prime}\right)=(1,0)$ in the moving frame $S^{\prime}$ has a coordinate $(x, c t)=(\gamma, \gamma \beta)$ in the rest frame $S$. The line connecting this point and the origin defines the $x^{\prime}$ axis. Another point $\left(x^{\prime}, c t^{\prime}\right)=(0,1)$ in the moving frame $S^{\prime}$ has a coordinate $(x, c t)=(\gamma \beta, \gamma)$ in the rest frame $S$. The line connecting this point and the origin defines the $c t^{\prime}$ axis. The angle between the $x$ and $\mathrm{x}^{\prime}$ axis is $\theta$, where $\tan \theta=\beta$. A unit length in the moving frame $S^{\prime}$ is equal to $\gamma \sqrt{1+\beta^{2}}=\sqrt{\frac{1+\beta^{2}}{1-\beta^{2}}}$ in the rest frame S.

To get a better understanding of Minkowski diagram, let us take a look at this example. Consider a stick of proper length $L$ in a moving frame S'. We would like to find the length of the stick in the rest frame S. Consider the figure below.



<image_2>

The stick is represented by the segment AC. The length $\mathrm{AC}$ is equal to $\sqrt{\frac{1+\beta^{2}}{1-\beta^{2}}} L$ in the $S$ frame. The stick length in the $S$ frame is represented by the line $A B$.

$$
\begin{aligned}
\mathrm{AB} & =\mathrm{AD}-\mathrm{BD} \\
& =A C \cos \theta-A C \sin \theta \tan \theta \\
& =L \sqrt{1-\beta^{2}}
\end{aligned}
$$
Context question:
1.  Using a Minkowski diagram, calculate the length of a stick with proper length $L$ in the rest frame, as measured in the moving frame.
Context answer:
\boxed{$\sqrt{1-\beta^{2}} L$}


Context question:
2.  Now consider the case in part A. Plot the time ct versus the position $x$ of the particle. Draw the $x^{\prime}$ axis and $c t^{\prime}$ axis when $\frac{g t}{c}=1$ in the same graph using length scale $x\left(c^{2} / g\right)$ and $c t\left(c^{2} / g\right)$.
Context answer:
\boxed{证明题}


Extra Supplementary Reading Materials:

Part D. Two Accelerated Particles

For this part, we will consider two accelerated particles, both of them have the same proper acceleration $g$ in the positive $x$ direction, but the first particle starts from $x=0$, while the second particle starts from $x=L$. Remember, DO NOT consider the flight time in this part.
Context question:
1.  After a while, an observer in the rest frame make an observation. The first particle's clock shows time at $\tau_{A}$. What is the reading of the second clock $\tau_{B}$, according to the observer in the rest frame.
Context answer:
\boxed{$\tau_{B}=\tau_{A}$}


Context question:
2.  Now consider the observation from the first particle's frame. At a certain moment, an observer that move together with the first particle observed that the reading of his own clock is $\tau_{1}$. At the same time, he observed the second particle's clock, and the reading is $\tau_{2}$. Show that

$$
\sinh \frac{g}{c}\left(\tau_{2}-\tau_{1}\right)=C_{1} \sinh \frac{g \tau_{1}}{c}
$$

where $C_{1}$ is a constant. Determine $C_{1}$.
Context answer:
\boxed{$C_{1}=\frac{g L}{c^{2}}$}


Context question:
3.  The first particle will see the second particle move away from him. Show that the rate of change of the distance between the two particles according to the first particle is

$$
\frac{d L^{\prime}}{d \tau_{1}}=C_{2} \frac{\sinh \frac{g \tau_{2}}{c}}{\cosh \frac{g}{c}\left(\tau_{2}-\tau_{1}\right)}
$$

where $C_{2}$ is a constant. Determine $C_{2}$.
Context answer:
\boxed{$C_{2}=\frac{g L}{c}$}


Extra Supplementary Reading Materials:

Part E. Uniformly Accelerated Frame

In this part we will arrange the proper acceleration of the particles, so that the distance between both particles are constant according to each particle. Initially both particles are at rest, the first particle is at $x=0$, while the second particle is at $x=L$.
Context question:
1.  The first particle has a proper acceleration $g_{1}$ in the positive $x$ direction. When it is being accelerated, there exists a fixed point in the rest frame at $x=x_{\mathrm{p}}$ that has a constant distance from the first particle, according to the first particle thoughout the motion. Determine $x_{p}$.
Context answer:
\boxed{$x_{p}=-\frac{c^{2}}{g_{1}}$}


Context question:
2.  Given the proper acceleration of the first particle is $g_{1}$, determine the proper acceleration of the second particle $g_{2}$, so that the distance between the two particles are constant according to the first particle.
Context answer:
\boxed{$g_{2}=\frac{g_{1}}{1+\frac{g_{1} L}{c^{2}}}$}


Context question:
3.  What is the ratio of time rate of the second particle to the first particle $\frac{d \tau_{2}}{d \tau_{1}}$, according to the first particle.
Context answer:
\boxed{$1+\frac{g_{1} L}{c^{2}}$}


Extra Supplementary Reading Materials:

Part F. Correction for GPS

Part E indicates that the time rate of clocks at different altitude will not be the same, even though there is no relative movement between those clocks.



According to the equivalence principle in general relativity, an observer in a small closed room could not tell the difference between a gravity pull $g$ and the fictitious force from accelerated frame with acceleration $g$. So we can conclude that two clocks at different gravitational potential will have different rate.

Now let consider a GPS satellite that orbiting the Earth with a period of 12 hours.
Context question:
1.  If the gravitational acceleration on the Earth's surface is $9.78 \mathrm{~m} \cdot \mathrm{s}^{-2}$, and the Earth's radius is $6380 \mathrm{~km}$, what is the radius of the GPS satellite orbit? What is the velocity of the satellite? Calculate the numerical values of the radius and the velocity.
Context answer:
\boxed{$r =2.66 \times 10^{7}$ and $v=3.87 \times 10^{3}$}


Context question:
2.  After one day, the clock reading on the Earth surface and the satellite will differ due to both special and general relativistic effects. Calculate the difference due to each effect for one day. Calculate the total difference for one day. Which clock is faster, a clock on the Earth's surface or the satellite's clock?
Context answer:
by general relativity effect, after one day, the difference is $4.55 \times 10^{-5} \mathrm{~s}$
by special relativity effect, after one day, the difference is $-7.18 \times 10^{-6} \mathrm{~s}$
The satelite's clock is faster with total $\Delta \tau=\Delta \tau_{g}+\Delta \tau_{s}=3.83 \times 10^{-5} \mathrm{~s}$
' as a scalar of type double
Traceback:    Traceback (most recent call last):
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1831, in _prepare_split_single
                  writer.write_table(table)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/arrow_writer.py", line 644, in write_table
                  pa_table = table_cast(pa_table, self._schema)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2272, in table_cast
                  return cast_table_to_schema(table, schema)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2223, in cast_table_to_schema
                  arrays = [
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2224, in <listcomp>
                  cast_array_to_feature(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 1795, in wrapper
                  return pa.chunked_array([func(chunk, *args, **kwargs) for chunk in array.chunks])
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 1795, in <listcomp>
                  return pa.chunked_array([func(chunk, *args, **kwargs) for chunk in array.chunks])
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2086, in cast_array_to_feature
                  return array_cast(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 1797, in wrapper
                  return func(array, *args, **kwargs)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 1949, in array_cast
                  return array.cast(pa_type)
                File "pyarrow/array.pxi", line 996, in pyarrow.lib.Array.cast
                File "/src/services/worker/.venv/lib/python3.9/site-packages/pyarrow/compute.py", line 404, in cast
                  return call_function("cast", [arr], options, memory_pool)
                File "pyarrow/_compute.pyx", line 590, in pyarrow._compute.call_function
                File "pyarrow/_compute.pyx", line 385, in pyarrow._compute.Function.call
                File "pyarrow/error.pxi", line 154, in pyarrow.lib.pyarrow_internal_check_status
                File "pyarrow/error.pxi", line 91, in pyarrow.lib.check_status
              pyarrow.lib.ArrowInvalid: Failed to parse string: 'Global Positioning System (GPS) is a navigation technology which uses signal from satellites to determine the position of an object (for example an airplane). However, due to the satellites high speed movement in orbit, there should be a special relativistic correction, and due to their high altitude, there should be a general relativistic correction. Both corrections seem to be small but are very important for precise measurement of position. We will explore both corrections in this problem.
              
              First we will investigate the special relativistic effect on an accelerated particle. We consider two types of frame, the first one is the rest frame (called $S$ or Earth's frame), where the particle is at rest initially. The other is the proper frame (called $S^{\prime}$ ), a frame that instantaneously moves together with the accelerated particle. Note that this is not an accelerated frame, it is a constant velocity frame that at a particular moment has the same velocity with the accelerated particle. At that short moment, the time rate experienced by the particle is the same as the proper frame's time rate. Of course this proper frame is only good for an infinitesimally short time, and then we need to define a new proper frame afterward. At the beginning we synchronize the particle's clock with the clock in the rest frame by setting them to zero, $t=\tau=0$ ( $t$ is the time in the rest frame, and $\tau$ is the time shown by particle's clock).
              
              By applying equivalence principle, we can obtain general relativistic effects from special relavistic results which does not involve complicated metric tensor calculations. By combining the special and general relativistic effects, we can calculate the corrections needed for a GPS (global positioning system) satellite to provide accurate positioning.
              
              Some mathematics formulas that might be useful
              
              - $\sinh x=\frac{e^{x}-e^{-x}}{2}$
              - $\cosh x=\frac{e^{x}+e^{-x}}{2}$
              - $\tanh x=\frac{\sinh x}{\cosh x}$
              - $1+\sinh ^{2} x=\cosh ^{2} x$
              - $\sinh (x-y)=\sinh x \cosh y-\cosh x \sinh y$
              
              
              
              - $\int \frac{d x}{\left(1-x^{2}\right)^{\frac{3}{2}}}=\frac{x}{\sqrt{1-x^{2}}}+C$
              - $\int \frac{d x}{1-x^{2}}=\ln \sqrt{\frac{1+x}{1-x}}+C$
              
              
              Part A. Single Accelerated Particle 
              
              Consider a particle with a rest mass $m$ under a constant and uniform force field $F$ (defined in the rest frame) pointing in the positive $x$ direction. Initially $(t=\tau=0)$ the particle is at rest at the origin $(x=0)$.
              Context question:
              1.  When the velocity of the particle is $v$, calculate the acceleration of the particle, $a$ (with respect to the rest frame).
              Context answer:
              \boxed{$a=\frac{F}{\gamma^{3} m}$}
              
              
              Context question:
              2.  Calculate the velocity of the particle $\beta(t)=\frac{v(t)}{c}$ at time $t$ (in rest frame), in terms of $F, m, t$ and $c$.
              Context answer:
              \boxed{$\beta=\frac{\frac{F t}{m c}}{\sqrt{1+\left(\frac{F t}{m c}\right)^{2}}}$}
              
              
              Context question:
              3.  Calculate the position of the particle $x(t)$ at time $t$, in term of $F, m, t$ and $c$.
              Context answer:
              \boxed{$x=\frac{m c^{2}}{F}\left(\sqrt{1+\left(\frac{F t}{m c}\right)^{2}}-1\right)$}
              
              
              Context question:
              4.  Show that the proper acceleration of the particle, $a^{\prime} \equiv g=F / m$, is a constant. The proper acceleration is the acceleration of the particle measured in the instantaneous proper frame.
              Context answer:
              \boxed{证明题}
              
              
              Context question:
              5.  Calculate the velocity of the particle $\beta(\tau)$, when the time as experienced by the particle is $\tau$. Express the answer in $g, \tau$, and $c$.
              Context answer:
              \boxed{$\beta=\tanh \frac{g \tau}{c}$}
              
              
              Context question:
              6. ( $\mathbf{0 . 4} \mathbf{~ p t s )}$ Also calculate the time $t$ in the rest frame in terms of $g, \tau$, and $c$.
              Context answer:
              \boxed{$t=\frac{c}{g} \sinh \frac{g \tau}{c}$}
              
              
              Extra Supplementary Reading Materials:
              
              Part B. Flight Time 
              
              The first part has not taken into account the flight time of the information to arrive to the observer. This part is the only part in the whole problem where the flight time is considered. The particle moves as in part A.
              Context question:
              1.  At a certain moment, the time experienced by the particle is $\tau$. What reading $t_{0}$ on a stationary clock located at $x=0$ will be observed by the particle? After a long period of time, does the observed reading $t_{0}$ approach a certain value? If so, what is the value?
              Context answer:
              \boxed{证明题}
              
              
              Context question:
              2.  Now consider the opposite point of view. If an observer at the initial point $(x=0)$ is observing the particle's clock when the observer's time is $t$, what is the reading of the particle's clock $\tau_{0}$ ? After a long period of time, will this reading approach a certain value? If so, what is the value?
              Context answer:
              \boxed{证明题}
              
              
              Extra Supplementary Reading Materials:
              
              Part C. Minkowski Diagram
              
              In many occasion, it is very useful to illustrate relativistic events using a diagram, called as Minkowski Diagram. To make the diagram, we just need to use Lorentz transformation between the rest frame $S$ and the moving frame $S^{\prime}$ that move with velocity $v=\beta c$ with respect to the rest frame.
              
              $$
              \begin{aligned}
              & x=\gamma\left(x^{\prime}+\beta c t^{\prime}\right), \\
              & c t=\gamma\left(c t^{\prime}+\beta x^{\prime}\right), \\
              & x^{\prime}=\gamma(x-\beta c t), \\
              & c t^{\prime}=\gamma(c t-\beta x) . \\
              & \gamma=\frac{1}{\sqrt{1-\frac{v^{2}}{c^{2}}}}
              \end{aligned}
              $$
              
              <image_1>
              
              Let's choose $x$ and $c t$ as the orthogonal axes. A point $\left(x^{\prime}, c t^{\prime}\right)=(1,0)$ in the moving frame $S^{\prime}$ has a coordinate $(x, c t)=(\gamma, \gamma \beta)$ in the rest frame $S$. The line connecting this point and the origin defines the $x^{\prime}$ axis. Another point $\left(x^{\prime}, c t^{\prime}\right)=(0,1)$ in the moving frame $S^{\prime}$ has a coordinate $(x, c t)=(\gamma \beta, \gamma)$ in the rest frame $S$. The line connecting this point and the origin defines the $c t^{\prime}$ axis. The angle between the $x$ and $\mathrm{x}^{\prime}$ axis is $\theta$, where $\tan \theta=\beta$. A unit length in the moving frame $S^{\prime}$ is equal to $\gamma \sqrt{1+\beta^{2}}=\sqrt{\frac{1+\beta^{2}}{1-\beta^{2}}}$ in the rest frame S.
              
              To get a better understanding of Minkowski diagram, let us take a look at this example. Consider a stick of proper length $L$ in a moving frame S'. We would like to find the length of the stick in the rest frame S. Consider the figure below.
              
              
              
              <image_2>
              
              The stick is represented by the segment AC. The length $\mathrm{AC}$ is equal to $\sqrt{\frac{1+\beta^{2}}{1-\beta^{2}}} L$ in the $S$ frame. The stick length in the $S$ frame is represented by the line $A B$.
              
              $$
              \begin{aligned}
              \mathrm{AB} & =\mathrm{AD}-\mathrm{BD} \\
              & =A C \cos \theta-A C \sin \theta \tan \theta \\
              & =L \sqrt{1-\beta^{2}}
              \end{aligned}
              $$
              Context question:
              1.  Using a Minkowski diagram, calculate the length of a stick with proper length $L$ in the rest frame, as measured in the moving frame.
              Context answer:
              \boxed{$\sqrt{1-\beta^{2}} L$}
              
              
              Context question:
              2.  Now consider the case in part A. Plot the time ct versus the position $x$ of the particle. Draw the $x^{\prime}$ axis and $c t^{\prime}$ axis when $\frac{g t}{c}=1$ in the same graph using length scale $x\left(c^{2} / g\right)$ and $c t\left(c^{2} / g\right)$.
              Context answer:
              \boxed{证明题}
              
              
              Extra Supplementary Reading Materials:
              
              Part D. Two Accelerated Particles
              
              For this part, we will consider two accelerated particles, both of them have the same proper acceleration $g$ in the positive $x$ direction, but the first particle starts from $x=0$, while the second particle starts from $x=L$. Remember, DO NOT consider the flight time in this part.
              Context question:
              1.  After a while, an observer in the rest frame make an observation. The first particle's clock shows time at $\tau_{A}$. What is the reading of the second clock $\tau_{B}$, according to the observer in the rest frame.
              Context answer:
              \boxed{$\tau_{B}=\tau_{A}$}
              
              
              Context question:
              2.  Now consider the observation from the first particle's frame. At a certain moment, an observer that move together with the first particle observed that the reading of his own clock is $\tau_{1}$. At the same time, he observed the second particle's clock, and the reading is $\tau_{2}$. Show that
              
              $$
              \sinh \frac{g}{c}\left(\tau_{2}-\tau_{1}\right)=C_{1} \sinh \frac{g \tau_{1}}{c}
              $$
              
              where $C_{1}$ is a constant. Determine $C_{1}$.
              Context answer:
              \boxed{$C_{1}=\frac{g L}{c^{2}}$}
              
              
              Context question:
              3.  The first particle will see the second particle move away from him. Show that the rate of change of the distance between the two particles according to the first particle is
              
              $$
              \frac{d L^{\prime}}{d \tau_{1}}=C_{2} \frac{\sinh \frac{g \tau_{2}}{c}}{\cosh \frac{g}{c}\left(\tau_{2}-\tau_{1}\right)}
              $$
              
              where $C_{2}$ is a constant. Determine $C_{2}$.
              Context answer:
              \boxed{$C_{2}=\frac{g L}{c}$}
              
              
              Extra Supplementary Reading Materials:
              
              Part E. Uniformly Accelerated Frame
              
              In this part we will arrange the proper acceleration of the particles, so that the distance between both particles are constant according to each particle. Initially both particles are at rest, the first particle is at $x=0$, while the second particle is at $x=L$.
              Context question:
              1.  The first particle has a proper acceleration $g_{1}$ in the positive $x$ direction. When it is being accelerated, there exists a fixed point in the rest frame at $x=x_{\mathrm{p}}$ that has a constant distance from the first particle, according to the first particle thoughout the motion. Determine $x_{p}$.
              Context answer:
              \boxed{$x_{p}=-\frac{c^{2}}{g_{1}}$}
              
              
              Context question:
              2.  Given the proper acceleration of the first particle is $g_{1}$, determine the proper acceleration of the second particle $g_{2}$, so that the distance between the two particles are constant according to the first particle.
              Context answer:
              \boxed{$g_{2}=\frac{g_{1}}{1+\frac{g_{1} L}{c^{2}}}$}
              
              
              Context question:
              3.  What is the ratio of time rate of the second particle to the first particle $\frac{d \tau_{2}}{d \tau_{1}}$, according to the first particle.
              Context answer:
              \boxed{$1+\frac{g_{1} L}{c^{2}}$}
              
              
              Extra Supplementary Reading Materials:
              
              Part F. Correction for GPS
              
              Part E indicates that the time rate of clocks at different altitude will not be the same, even though there is no relative movement between those clocks.
              
              
              
              According to the equivalence principle in general relativity, an observer in a small closed room could not tell the difference between a gravity pull $g$ and the fictitious force from accelerated frame with acceleration $g$. So we can conclude that two clocks at different gravitational potential will have different rate.
              
              Now let consider a GPS satellite that orbiting the Earth with a period of 12 hours.
              Context question:
              1.  If the gravitational acceleration on the Earth's surface is $9.78 \mathrm{~m} \cdot \mathrm{s}^{-2}$, and the Earth's radius is $6380 \mathrm{~km}$, what is the radius of the GPS satellite orbit? What is the velocity of the satellite? Calculate the numerical values of the radius and the velocity.
              Context answer:
              \boxed{$r =2.66 \times 10^{7}$ and $v=3.87 \times 10^{3}$}
              
              
              Context question:
              2.  After one day, the clock reading on the Earth surface and the satellite will differ due to both special and general relativistic effects. Calculate the difference due to each effect for one day. Calculate the total difference for one day. Which clock is faster, a clock on the Earth's surface or the satellite's clock?
              Context answer:
              by general relativity effect, after one day, the difference is $4.55 \times 10^{-5} \mathrm{~s}$
              by special relativity effect, after one day, the difference is $-7.18 \times 10^{-6} \mathrm{~s}$
              The satelite's clock is faster with total $\Delta \tau=\Delta \tau_{g}+\Delta \tau_{s}=3.83 \times 10^{-5} \mathrm{~s}$
              ' as a scalar of type double
              
              The above exception was the direct cause of the following exception:
              
              Traceback (most recent call last):
                File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1456, in compute_config_parquet_and_info_response
                  parquet_operations = convert_to_parquet(builder)
                File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1055, in convert_to_parquet
                  builder.download_and_prepare(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 894, in download_and_prepare
                  self._download_and_prepare(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 970, in _download_and_prepare
                  self._prepare_split(split_generator, **prepare_split_kwargs)
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1702, in _prepare_split
                  for job_id, done, content in self._prepare_split_single(
                File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1858, in _prepare_split_single
                  raise DatasetGenerationError("An error occurred while generating the dataset") from e
              datasets.exceptions.DatasetGenerationError: An error occurred while generating the dataset